For the initial flaw assumptions, JSSG-2006 paragraph A3.12.1
states: “Only one initial flaw in the most critical hole and one initial flaw
at a location other than a hole need be assumed to exist in any structural
element. Interaction between these
assumed initial flaws need not be considered.”
Obviously, interaction between these cracks can be disregarded because
these cracks are not assumed to occur simultaneously, although each of them may
occur separately. However, more than
one initial flaw may occur if due to fabrication and assembly operations two or
more adjacent elements can contain the same initial damage at the same
location. Note that each of the
adjacent elements has only one flaw. JSSG-2006 paragraph A3.12.1 further
states: “For multiple and adjacent elements, the initial flaws need not be
situated at the same location, except for structural elements where fabrication
and assembly operations are conducted such that flaws in two or more elements
can exist at the same location.”
The previous statement that interaction between assumed initial
flaws need not be considered is not repeated here because these cracks will
interact as they occur simultaneously.
In principle, the damage tolerance calculation should consider this
interaction. However, a rigorous
treatment of this problem is prohibitive in most cases. Consider, e.g., a skin with a reinforcement
as in Figure 5.5.12. Because of assembly drilling, both holes should be assumed flawed
(Figure 5.5.12a).
If both elements carry the same stress, there will be hardly any load
transfer initially. Hence, the stress
intensities for both flaws will be equal, implying that initially both will
grow at the same rate.
If the two cracks continue to grow simultaneously in a
dependent manner, their stress-intensity factors (K) will eventually be different (e.g., K of the reinforcement would increase faster if only for the finite
size effect). This means that in a
given cycle the rate of growth would be different for the two cracks resulting
in different crack sizes. Since it
cannot be foreseen prior how the crack sizes in the two members develop, it
would be necessary to develop K-solutions
for a range of crack sizes and a range of crack size ratios in the two members.
Figure 5.5.12. Interaction of Cracks
EXAMPLE
5.5.1: Interacting Cracks
Assume the crack size in the
skin is as, the crack size
in the reinforcement ar. For a given value of ar, the K for
the skin crack would be calculated as a function of as. This
calculation would be repeated for a range of ar sizes. The
same would be done for the reinforcement crack and a range of as values. For any given combination of ar and as, the two stress-intensity factors then can be found
by interpolation.
Although the consequences of crack interaction should be
evaluated, routine calculations may be run without interaction of cracks
[Smith, et al., 1975; Smith, 1974].
Obviously, the calculation procedure is much simpler if interaction can
be ignored. However, the procedure may
give unconservative results.
If either element remained uncracked, the stress-intensity
factor in the cracked element would be much lower because there would be load
transferred from the cracked element to the uncracked element. Obviously, the stress-intensity factor in
the cracked skin of Example 5.5.1 would be the
lowest. The cracks could be grown as if
the other element was uncracked and crack growth would be slower.
Finally, the reinforcement could be totally cracked. Interaction must be taken into account,
i.e., the crack in the skin would be treated now for the case of a failed
reinforced panel (e.g., stringer reinforced structure with middle stringer
failed).
This means that two analysis have to be made for a K-determination, one with the
reinforcement uncracked, one with the reinforcement failed. If the two independent crack growth analyses
show that the reinforcement has failed, the analysis of the skin is changed
appropriately.